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ECCouncil C-THR92-2105 - SAP Certified Application Associate - SAP SuccessFactors People Analytics Embedded Edition 3H/2021 Braindumps

SAP C-THR92-2105 - SAP Certified Application Associate - SAP SuccessFactors People Analytics Embedded Edition 3H/2021 Braindumps

  • Certification Provider:SAP
  • Exam Code:C-THR92-2105
  • Exam Name:SAP Certified Application Associate - SAP SuccessFactors People Analytics Embedded Edition 3H/2021 Exam
  • Total Questions:765 Questions and Answers
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NEW QUESTION: 1
Refer to the exhibit.

An administrator creates a security policy that isolates their financial application from accessing the Internet When viewing the policy in Prism Central, several connections from the application are outbound to the Internet.
What is causing this issue with the policy?
A. The Activate box was not checked in the rule, so it is not enforcing.
B. The 0.0.0.0 address was not specified in the outbound rule.
C. The blocked connections are illustrated for information only.
D. The policy has been left in monitor mode instead of enforcing mode.
Answer: D
Explanation:
Explanation
https://portal.nutanix.com/page/documents/details?targetId=Prism-Central-Guide-Prism-v510:mul-security-poli

NEW QUESTION: 2
Which two statements correctly describe Spine-Leaf switch topologies? (Choose two.)
A. Oversubscription, if it occurs, is more likely to be found in the leaf switches.
B. Spine-leaf topologies can utilize layer 2 or layer 3 switching for inter-connectivity.
C. Spine-leaf topologies must utilize layer 3 switching for inter-connectivity.
D. Oversubscription, if it occurs, is more likely to be found in the spine switches.
Answer: A,B

NEW QUESTION: 3
View the Exhibit and examine the structure of the PRODUCTS tables.
You want to generate a report that displays the average list price of product categories where the average list price is less than half the maximum in each category.
Which query would give the correct output?
A. SELECT prod_category, avg(prod_list_price)
FROM products
GROUP BY prod_category
HAVING avg(prod_list_price) > ANY
(SELECT max(prod_list_price)/2
FROM products);
B. SELECT prod_category, avg(prod_list_price)
FROM products
GROUP BY prod_category
HAVING avg(prod_list_price) > ANY
(SELECT max(prod_list_price)/2
FROM products
GROUP BY prod_category);
C. SELECT prod_category, avg(prod_list_price)
FROM products
GROUP BY prod_category
HAVING avg(prod_list_price) < ALL
(SELECT max(prod_list_price)/2
FROM products
GROUP BY prod_category);
D. SELECT prod_category, avg(prod_list_price)
FROM products
HAVING avg(prod_list_price) < ALL
(SELECT max(prod_list_price)/2
FROM products
GROUP BY prod_category);
Answer: C
Explanation:
Explanation/Reference:
Explanation:
Using the ANY Operator in Multiple-Row Subqueries
The ANY operator (and its synonym, the SOME operator) compares a value to each value returned by a subquery.
<ANY means less than the maximum.
>ANY means more than the minimum.
=ANY is equivalent to IN
Using the ALL Operator in Multiple-Row Subqueries
The ALL operator compares a value to every value returned by a subquery.
>ALL means more than the maximum and
<ALL means less than the minimum.
The NOT operator can be used with IN, ANY, and ALL operators.

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